2x^2+14x-7.5=0

Solution for 2x^2+14x-7.5=0 equation:

2x^2+14x-7.5=0

a = 2; b = 14; c = -7.5;
Δ = b2-4ac
Δ = 142-4·2·(-7.5)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-16}{2*2}=\frac{-30}{4}
=-7+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+16}{2*2}=\frac{2}{4}
=1/2
$